Pat, either I do not understand your answer or I did not make my
question clear.  I believe your suggestion would return users within a
distance of New York.  But what I am trying to do is return users
within a distance of both New York and London.  Essentially, trying
something like this (which does not work):

:geo => [ [ @ny.lat, @ny.lng], [ @london.lat, @london.lng ] ]

Thanks for your help.

On May 18, 12:39 am, Pat Allan <[email protected]> wrote:
> Hi Anatoly
>
> What I'm thinking is that you make Location the searchable model - so  
> have all references to users from within the Location define_index  
> block.
>
> And then, do a grouped search - by user_id (which should be set up as  
> an attribute), and sort the overall results by distance.
>
> Location.search(
>    :geo            => [[email protected], @ny.lng],
>    :group_function => :attr,
>    :group_by       => "user_id",
>    :order          => "@geodist ASC, @relevance DESC"
> )
>
> Add in :without => {:user_id => @user.id} to exclude the focused user,  
> if needed. Now, I've no idea how nicely geo-location searching plays  
> with grouping, but it's worth a shot, right? And, should it all go to  
> plan, each location will have a distinct user.
>
> @locations.each_with_geodist do |location, distance|
>    # location.user
> end
>
> Hope this helps.
>
> Cheers
>
> --
> Pat
>
> On 17/05/2009, at 8:52 PM, anatoly wrote:
>
>
>
> > Another distance question.  As far as I can tell there is no clean
> > solution for this, so wondering what suggestions may come out.
>
> > I have a User model which has many Locations.
> > So a User may have a Location in New York and a Location in London.
>
> > How would I go about doing a search for other Users within X distance
> > of either New York or London, and then order the results by distance?
>
> > One way of solving for this would be to do to separate searches,
> > combine the results, and order by distance.  However, since there can
> > be other search criteria, the combined results would have to be sorted
> > by weight and then distance.
>
> > I am not sure if this will work right, and not exactly sure how to
> > even do that.
>
> > Any other suggestions?
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