ImgBurn has the steps fairly well laid out, or so I thought.  I used the
feature 'Create image file from disc' to create the .iso file, which was
stored in a new folder.  I then went to the feature 'Write image file to
disc', selected the stored .iso file, put a new DVD in the drive, pointed
ImgBurn at that drive and let it go.  I got the .iso file on the DVD, versus
an exact copy of the original DVD.  There weren't any other features to
chose from, so, not needing anymore shiny coasters, I didn't try that again.
Instead, opened Power2Go and did the disc copy.  Still don't know what's the
purpose of creating and burning via an .iso file and why it isn't the same
as using a D-T-D utility.

Thanks for responding.

-----Original Message-----
From: TK [mailto:[email protected]] 
Sent: Sunday, April 01, 2012 10:31 AM
To: Roger Sears
Cc: Rich
Subject: Off-list: Re: [Thinkpad] .iso copy versus disc-to-disc

At 4/1/2012 12:57 PM, Roger Sears wrote:
>Seeing the recent post about making and then using an iso. image to create
>an exact copy of a CD or DVD, and having screwed up that process when I
>tried it using ImgBurn, I've got to ask, why doesn't just making a
>disc-to-disc copy accomplish the same thing?
>
>I finally resorted to the D-T-D copy after I (must of) screwed up the .iso
>burn step - all I got on the new DVD was a copy of the .iso file I had
>initially created.

If you got a copy of the .iso file on the new disc, you did it wrong.  You
should not burn the .iso file.  You should burn a disk image using the .iso
file.  Burning programs have a separate feature for this.  If you are e.g.
dragging an .iso file in a file window in your burning program, you're just
going to get a file system with an .iso file in it, which is not what you
want.  

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