Hi Tobias
I know the way I have done it may seem a little counter-intuitiv. The
reason I cant do it the other way around is that in the larger TW
where I am trying to implement the solution I only "know" each
tiddler's parent tiddler(s) and I can't think of an easy way to
reverse this (ei I don't what to sort through all tiddlers to make
sure I've caught all of a tiddler's childeren)
Allthough you could probably do what you are suggesting using the code
below. The lack of numbering is however kind of a dealbreaker because
I need the trees created to be very precise as to what tiddler is own
by what.
----
/%
!out
$1
!end
%/<<tiddler ShowList##out with: {{
var out=[];
var target="$1";
var tids=store.getTiddlers();
for (var i=0;i<tids.length;i++) {
var a=tids[i].fields.field;
var b=tids[i].fields.field2;
if (a&& a.contains(target))
out.push("#[["+tids[i].title+"]]");
if (b && b.contains(target))
out.push("#[["+tids[i].title+"]]");
}
out.join("\n");}}>>
---
I hope this made sense. As I am writing this it is kind of late in
Denmark.
regards
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