Good evening. Just a question of curiosity. Can this filter be simplified? For example, can all[current] be "factored out" so it does not need to appear twice?
[is[current]has[birt_date]] [is[current]has[birt_plac]] In Boolean, I think this would be [(A and B) or (A and C)] == [A and (B or C)], but I'm not sure how to write [A and (B or C)] in filter. -- You received this message because you are subscribed to the Google Groups "TiddlyWiki" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/tiddlywiki/dec703f5-d219-4111-8579-ea5ddb9dc6fbn%40googlegroups.com.
