That's really helpful - thank you saq! On Wednesday, 13 January 2021 at 19:55:34 UTC [email protected] wrote:
> @si > > This is a really rough and quick attempt, there are probably simpler ways: > > \define showAncestors() > <$list filter="[enlist<mylist>first[]]"> > <ul><li> > <<currentTiddler>> > <$set name="mylist" filter="[enlist<mylist>rest[1]]"> > <<showAncestors>> > </$set> > </li></ul> > </$list> > \end > > \define getAncestors() > <$list filter="[all[current]get[parent]!is[blank]]" emptyMessage="""<$set > name="mylist" > filter="[enlist<mylist>reverse[]]"><<showAncestors>></$set>"""> > <$log/> > <$set name="mylist" filter="[enlist<mylist>] [<currentTiddler>]"> > <<getAncestors>> > </$set> > </$list> > \end > > <$set name="mylist" filter="[<currentTiddler>]"> > <<getAncestors>> > </$set> > > Apologies for the formatting, it's a bit of a struggle on a touch device. > On Wednesday, January 13, 2021 at 5:17:37 PM UTC+1 si wrote: > >> I'm using Streams, where tiddlers are related hierarchically, and I'm >> trying to create a macro that will return the ancestors of the current >> tiddler in a formatted bullet list. >> >> So for example if I had a Stream like this: >> >> - A >> - B >> - E >> - C >> - D >> - F >> >> Then the macro, when applied to tiddler F, would return this: >> >> - A >> - D >> - F >> >> I know that I can use the following kin filter to return a list of the >> ancestors: [kin:stream-list:to:<currentTiddler>]. What I am struggling to >> figure out is how to turn it into a list that is actually formatted as per >> the example above. >> >> Can anyone help me out here? Thanks in advance. >> >> > -- You received this message because you are subscribed to the Google Groups "TiddlyWiki" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/tiddlywiki/f6f1e5f5-e34c-47b2-825a-81ff86739231n%40googlegroups.com.
