Hi Eskha thanks for the reply.

Unfortunately that's not quite what I was asking. The filter has to take 
the title as an input, it can't be used as a parameter. Take a look at 
Soren's comment as he explains it better than I can, or maybe look at the 
Tidgraph docs to see how it works: 
https://ihm4u.github.io/tw5plugs/#Custom%20Mode%20Demo.

The filter would have to look like this:

<currentTiddler>some[]filter[]expression[]

Where <currentTiddler> can't be used anywhere else in the expression.

On Tuesday, 2 March 2021 at 15:01:55 UTC Eskha wrote:

> Hello si,
>
> Not sure if I have well understood what you wan to achieve.
> Wouldn't the following call do the job?
>
> <$list filter="[prefix<currentTiddler>sort[title]]" 
> template="$:/core/ui/ListItemTemplate"/>
>
> (You can change the template or use the <$list ...> ... </$list> syntax if 
> you prefer.)
>
> Best regards,
>
> Eskha
>
> Le mardi 2 mars 2021 à 00:16:22 UTC+1, si a écrit :
>
>> Thanks for the replies.
>>
>> Soren is correct - the value "root/folder" has to be the input tiddler. I 
>> was struggling to express this well so thanks @Soren.
>>
>> The filter itself does not need to create a tree. It just needs to look 
>> at the input tiddler, then return any tiddlers in the wiki of the form 
>> "<input tiddler>/blah". As Soren mentioned it doesn't look like it's 
>> actually possible.
>> On Monday, 1 March 2021 at 18:52:59 UTC si wrote:
>>
>>>
>>> Hi all,
>>>
>>> I am trying to figure out if there is a filter expression that will act 
>>> on an input tiddler like "root/folder" and return all tiddlers of the form 
>>> "root/folder/.*" (i.e. root/folder/subfolder1, root/folder/subfolder2 etc).
>>>
>>> I can't figure this one out, so any help would be amazing.
>>>
>>> *My specific use case if you're interested:*
>>>
>>> I have a directory structure representing in my wiki, which I currently 
>>> display with the tree macro <https://tiddlywiki.com/#tree%20Macro>. I 
>>> was trying to see if I could use Tidgraph 
>>> <https://ihm4u.github.io/tw5plugs/> to display the directory structure, 
>>> and I can see that I will need a filter that works as described above.
>>>
>>> Thanks in advance for your help.
>>>
>>

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