Mats suggestion is one I use.
Another trick is to use count to get the total number T of items then use a
range operator from 1 to N, in which the current tiddler will be the item
number.
However you then need to retrieve the nth[N] item from the list.
Regards
Tones
On Tuesday, 23 March 2021 at 21:24:41 UTC+11 Mat wrote:
> You can use this to find the position of an item in a list
>
> +[allbefore<item>count[]add[1]]
>
> e.g
>
> {{{ one two three four five +[allbefore[four]count[]add[1]] }}} ----> 4
>
> Not sure it's the optimal solution, I just made it up.
>
> <:-)
>
>
>
> On Tuesday, March 23, 2021 at 10:57:48 AM UTC+1 Mohamed Amin wrote:
>
>> Hi,
>>
>> Is there a way to get the position of an item in a "list field"?
>>
>> More info:
>> Recently I've discovered the "nth" filter operator
>> <https://tiddlywiki.com/#nth%20Operator>, and one of the use case I
>> immediately think about was to "iterate" through items in multiple related
>> "list fields"
>>
>> Take the following example (not a real one, just to get the idea clear):
>> If a family needs to manage its friends, each family member's Tiddler
>> will have the following fields:
>> 1- friend-names : "list field" contains ALL friends
>> 2- friendships-start-date : "list field" where the "position" of the date
>> determine the friend's names
>> 3- friendships-meter : "list field" where the "position" of the %
>> determine the friend's names
>>
>> Ex.
>> friend-names : [[alex]] [[andy]] [[john]]
>> [[evan]]
>> friendships-start-date : [[Mar2015]] [[Dec2017]] [[Nov2016]]
>> [[Feb2011]]
>> friendships-meter [[70]] [[30]] [[60]]
>> [[90]]
>>
>> Now I can use the filter "[contain:friend-name[alex]]" to get all family
>> members who is a friend with "alex".
>> And if I know the <<position>> of "alex" in the "friend-names" field, I
>> can get the rest of the data corresponding to it for the currentTiddler
>> using a filter like:
>> "[all[current]get[friendships-meter]enlist-input[]nth<position>]"
>>
>> Regards
>>
>>
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