Or this;
<$list filter="[[ActionDeleteTiddlerWidget]] [[ActionListopsWidget]]
+[!sort[modified]]">
<$link/> {{!!modified}}<br>
</$list>
;Newer test
<$list filter="[[ActionDeleteTiddlerWidget]] [[ActionListopsWidget]]
+[sort[modified]] +[last[]]">
</$list>
;Older test
<$list filter="[[ActionDeleteTiddlerWidget]] [[ActionListopsWidget]]
+[sort[modified]] +[first[]]">
</$list>
Tones
On Wednesday, 5 May 2021 at 17:05:03 UTC+10 Mohammad wrote:
> Hi Saq,
>
> Very clever! Both works!
>
> On Wed, May 5, 2021 at 11:08 AM Saq Imtiaz <[email protected]> wrote:
>
>> Does this do what you need?
>>
>> Aa Bb +[nsort[modified]limit[1]]
>>
>>
> I am wondering why we did not try this which was available from 2015? ;-)
>
>
>
>> Or try something like this in 5.1.24 pre-release:
>>
>> Aa Bb :sort:date[get[modified]] +[limit[1]]
>>
>
> Great! So, we can use the new named prefix :sort?
> Is it possible to have multiple steps filter like below
>
> filter1 :filter[step2] :filter[step3]
>
>
>
>
>
>>
>>
>> See https://tiddlywiki.com/prerelease/#Sort%20Filter%20Run%20Prefix
>> On Wednesday, May 5, 2021 at 7:41:37 AM UTC+2 Mohammad wrote:
>>
>>> Back to winter 2019, when we were working on the Commander plugin we
>>> needed a comparison between two tiddlers to see which is greater. See [1]
>>> The best solution we found (by BTC) at that time was as below [2] (still
>>> works and is part of Commander)
>>>
>>>
>>> <$set name="tidBMod" value={{{ [[Bb]get[modified]] }}}>
>>> <$set name="tidAMod" value={{{ [[Aa]get[modified]] }}}>
>>> <$list filter="[<tidAMod>] [<tidBMod>]
>>> +[nsort[]last[1]removesuffix<tidAMod>]">
>>> Yes, Aa is newer
>>> </$list>
>>> <$list filter="[<tidAMod>] [<tidBMod>]
>>> +[nsort[]last[1]removesuffix<tidBMod>]">
>>> No, Aa is older
>>> </$list>
>>> </$set>
>>> </$set>
>>>
>>>
>>> With the advent of many new filter operator, I want to know if there is
>>> a shorter and more semantic solution can be found today Apr 2021
>>>
>>> I thought about the below solution and it works in TW 5.1.23
>>>
>>> <$vars dtb={{{[[Bb]get[modified]]}}}>
>>>
>>> <$list
>>> filter="[[Aa]get[modified]compare:integer:gt<dtb>then[Aa]else[Bb]]">
>>> <<currentTiddler>> is newer!
>>> </$list>
>>>
>>> </$vars>
>>>
>>>
>>> But I am wondering if we could use :filter or some other operator to
>>> drop the $vars and dtb and perform the comparison in single $list
>>> Note Aa and Bb are two tiddlers
>>>
>>>
>>>
>>> Best wishes
>>> Mohammad
>>>
>>> [1] https://groups.google.com/g/tiddlywiki/c/9QQvkJkLogA/m/3AGSBBJKBgAJ
>>> [2] https://groups.google.com/g/tiddlywiki/c/9QQvkJkLogA/m/UbIgaSFSBgAJ
>>>
>>> --
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