I think that may be it (or very close)
i.e.
ara1 = [a,b,c,d,e]
ara2 = [c,e]

aRes = [a, b, d]

I tried to google a answer, but without the proper terminology I did
not get any usable results.

Thank You for the feedback,

Mike

On Apr 25, 5:41 pm, "Mark S." <[email protected]> wrote:
> I guess you mean a method to produce an array by removing all items
> from array 1 that are not in array 2 ?
>
> Something like this?
>
> function ArraySubtract(ara1,ara2) {
>   var aRes = new Array() ;
>   for(var i=0;i<ara1.length;i++) {
>     if( ! (ara2.contains(ara1[i]) )) {
>       aRes.push(ara1[i]) ;
>     }
>   }
>   return aRes ;
>
> }
>
> Mark
>
> On Apr 25, 8:48 am, Mike <[email protected]> wrote:
>
> > Javascript or jQuery - compare / subtract (2) arrays, output to a 3rd
> > array?
>
> > I am having a hard time finding a reference as to what is the best
> > practice for this. . .
>
> > Any thoughts or suggestion?
>
> > Mike
>
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