Hi axelm,
What about:
<<forEachTiddler
where 'tiddler != context.inTiddler &&
tiddler.tags.containsAll(context.inTiddler.tags)'
>>
(The sort().join("]]") approach doesn't seem to work for me - but
perhaps you need it for some other reason?).
cmari
On Dec 30, 7:00 pm, Måns <[email protected]> wrote:
> Hi axelm
>
> > <<forEachTiddler
> > where 'tiddler != context.inTiddler &&
> > tiddler.tags.sort().join("]]") ==
> > context.inTiddler.tags.sort().join("]]")'
> > so that, instead of listing the tiddlers that have all the tags of the
> > calling tiddler, to listing the tiddlers that have all the tags but
> > could also have additional tags?
>
> untested!
> I would add "&& tiddler.tags.contains("SomeTag")" to the formula ,
> maybe just after "!= context.inTiddler" (without the outer
> qoutes...)http://tiddlywiki.abego-software.de/#WhereClauseExamples
>
> Cheers Måns Mårtensson
--
You received this message because you are subscribed to the Google Groups
"TiddlyWiki" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/tiddlywiki?hl=en.
