Wow! Two greats answers, and it's the same strategy. Thanks to M. Shulman and M. PMario for the code and the explications.
I try the code and ... TypeError: jQuery.plot is not a function I have to think about that. My Javascript and Jquery knowledge is very small. LaRaison On Mar 28, 5:22 pm, PMario <[email protected]> wrote: > <script> > var d1 = []; > for (var i = 0; i < 14; i += 0.5) > d1.push([i, Math.sin(i)]); > var d2 = [[0, 3], [4, 8], [8, 5], [9, 13]]; > // a null signifies separate line segments > var d3 = [[0, 12], [7, 12], null, [7, 2.5], [12, 2.5]]; > jQuery.plot( jQuery("#placeholder"), [ d1, d2, d3 ]); > </script> > > may work. > > since $ is only a "shortcut" for jQuery replace something like > > $('#someID').someFunctionName(); > with > jQuery('#someID').someFunctionName(); and it should work. > > since $.plot() is a jQuery plugin it should be possible to use > jQuery.plot() > > the above is not tested. > -m -- You received this message because you are subscribed to the Google Groups "TiddlyWiki" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/tiddlywiki?hl=en.
