Hello,
I traced down the code and the problem is on the JSON.parse part.
After the substituteVariableReferences execution, JSON.parse will receive
the following string:
"{"text":"Now↵Try
↵LB","bag":"default","revision":"0","type":"text/vnd.tiddlywiki","title"
Which does not seems to be a valid JSON string.
The code that fails is like this
// Make the clone of the template
var make = this.wiki.getTiddlerAsJson(this.maketidTemplate);
debugger;
var tempTest =this.substituteVariableReferences(make);
var makeClone = JSON.parse(tempTest);
The problem is that substituteVariableReferences returns that string with
those unexpected characters. Maybe the substituteVariableReferences should
return \n instead?
El martes, 4 de noviembre de 2014 12:38:07 UTC+1, Jeremy Ruston escribió:
>
> Hi Danielo
>
> There's no problem that I can see with the snippet you posted above. Can
> you put up a minimal test case?
>
> Best wishes
>
> Jeremy
>
>
> On Tue, Nov 4, 2014 at 11:27 AM, Danielo Rodríguez <[email protected]
> <javascript:>> wrote:
>
>> The error is much more concise in firefox:
>>
>> SyntaxError: JSON.parse: bad control character in string literal at line
>> 1 column 13 of the JSON data
>>
>> Why?
>>
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>
>
> --
> Jeremy Ruston
> mailto:[email protected] <javascript:>
>
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