I'm actually using those attributes on the outer element to position the 
inner element x% and y% releative to the outer svg.  However, I will 
experiment if there's some way I can otherwise position them.

On Thursday, March 10, 2016 at 2:27:37 PM UTC-5, Eric Shulman wrote:
>
>
> On Thursday, March 10, 2016 at 9:34:22 AM UTC-8, Matthew Lauber wrote:
>>
>> Anyone have a easy solution to using the $link element inside a <svg>? 
>>  Attached I've got my testing example.  An empty <a> tag works just fine, 
>> but using <$link> in its place causes the bow not to render.  I't possible 
>> I've missed something obvious, but I've been banging my head against the 
>> wall.
>>
>
> Your svg definitions have two *nested* <svg>...</svg> elements.  You have:
>
> <svg ...>
>    <a>
>       <svg ...>
>       ...
>       </svg>
>    </a>
> </svg>
>
> and
>
> <svg ...>
>    <$link ...>
>       <svg ...>
>       ...
>       </svg>
>    </$link>
> </svg>
>
> If you remove the outer <svg></svg> pair, the $link widget and the <a> 
> element work as expected (i.e., creates a link to a tiddler or an href, 
> respectively).  It seems the the only thing the outer <svg> element adds is 
> width="100%" height="100%", but you should be able to simply move those 
> attributes to the inner <svg> so the image will appear the same size as 
> before.
>
> enjoy,
> -e
> Eric Shulman
> TiddlyTools / ELS Design Studios
> InsideTiddlyWiki: The Missing Manuals
>

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