>
>
> It is created using the NOW macro. It does not matter how it looks like,
> as long as it is easy to calculate the time diff in minutes between them.
> I wanted to avoid creating a custom JS macro, but if it is the only way...
>
Danielo,
Perhaps something like this would serve as a starting place for what you
want...
(function(){
/*\
Calculates the difference between two dates
<<datediff date1 date2 days>>
\*/
exports.name = "datediff";
exports.params = [
{ name: "date1" },
{ name: "date2"},
{ name: "units"},
];
/*
Run the macro
*/
exports.run = function(date1,date2,units) {
// If no date supplied use current date
if (date2=="") {
var d2=new Date();
var date2 = d2.toLocaleDateString();
}
if (date1==""){
var d1=new Date(5/1/1984);
}
var d1 = new Date(date1);
var d2 = new Date(date2);
switch(units){
case "weeks":
var t2 = d2.getTime();
var t1 = d1.getTime();
result = Math.floor(parseFloat((t2-t1)/(24*3600*1000*7))*100)/100+" weeks";
break;
case "minutes":
var t2 = d2.getTime();
var t1 = d1.getTime();
result = parseInt((t2-t1)/(60*1000)) + " minutes";
break;
case "months":
var d1Y = d1.getFullYear();
var d2Y = d2.getFullYear();
var d1M = d1.getMonth();
var d2M = d2.getMonth();
var d1D = d1.getDate();
var d2D = d1.getDate();
result =Math.floor(((d2M+12*d2Y+d2D/30)-(d1M+12*d1Y-d1D/30))*100)/100 + "
months";
break;
case "years":
var d1Y = d1.getFullYear();
var d2Y = d2.getFullYear();
var d1M = d1.getMonth();
var d2M = d2.getMonth();
var d1D = d1.getDate();
var d2D = d1.getDate();
result =Math.floor(((d2M/12+d2Y+d2D/365)-(d1M/12+d1Y-d1D/365))*100)/100 + "
years";
// result=parseFloat(d2.getFullYear()-d1.getFullYear()) + " years";
break;
default:
var t2 = d2.getTime();
var t1 = d1.getTime();
result = parseInt((t2-t1)/(24*3600*1000)) + " days";
}
return result;
};
})();
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