On Monday, October 2, 2017 at 3:02:23 PM UTC+2, Jed Carty wrote: > > I have run into this problem myself a few times and never came up with a > satisfactory answer. >
Hm, that's surprising to hear. > The closest I came up with was to define, using $set with a filter, the > parts that you want to remove and then just subtracting them. I haven't > come up with a way to make this work well. > But that is what my failed attempt tried. How would you do it with the above case? .... @everyone: Would it make sense to make a github request for this (let a lone a PR of course). It occurs to me that a times character (*) would make syntactic sense for distribution: "[op*[a b c]]" = "[op[a]] [op[b]] [op[c]]" <:-) -- You received this message because you are subscribed to the Google Groups "TiddlyWiki" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/tiddlywiki. To view this discussion on the web visit https://groups.google.com/d/msgid/tiddlywiki/3babee66-84cc-4b0e-a3fa-c5ec0d236bcf%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
