Hello Mark, thanks a lot,
the second solution works, in my constellation the first one somehow did
not....
Yours Jan
Am 20.06.2018 um 01:04 schrieb 'Mark S.' via TiddlyWiki:
Well, this works, though it may not be what you have in mind:
|
\define firstlevel(param1:"the parameter")
<<secondlevel "$param1$">>
\end
\define secondlevel(param1:"the other parameter)
And here I need $param1$
\end
<<firstlevel "you">>
|
You could also package the first parameter as a variable:
|
\define firstlevel(param1:"the parameter")
<$vars myvar="$param1$">
<<secondlevel>>
</$vars>
\end
\define secondlevel()
Andhere I need $(myvar)$
\end
<<firstlevel "you">>
|
Notice that when you use a parameter passed as a parameter you use
$parameter$ but when you use a variable (I'm sure I'm using the
terminology) then you use $(variable)$. Both forms, $param$ and
$(variable)$ are only good when called INSIDE a macro.
HTH
-- Mark
On Tuesday, June 19, 2018 at 3:20:49 PM UTC-7, Jan wrote:
Hi!
How do I get this to work?
\define firstlevel(param1:"the parameter")
<<secondlevel>>
\end
\define secondlevel()
And here I need $param1$
\end
<<firstlevel "you">>
Thanks!
Jan
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