On Feb 10, 2007, at 5:09 AM, Muhammad Azhar wrote:
Hi all,
I'm thinking that my programming logic might be wrong which is
why the compiler gave me this warning:
XxxxC.nc: In function `Receive.receive':
XxxxC.nc:117: warning: passing argument 2 of `AMSend.send' from
incompatible pointer type
I read through the Receive interface and was told that if I
wanted to return the same message_t packet buffer for later use by
the same signalling component, I can do so provided I have copied
the data that I wanted. In my program, I wanted selected nodes
with certain IDs to modify the data that they received from another
node and send it to another different node - hence, in my
Receive.receive(message_t* bufPtr, void* payload, uint8_t len), I
signalled AMSend.send after I have modified the data... This was
what I did:
message_t* tempBuffer;
struct* something = (struct*)payload;
something->data = something->value + count - something->data
memcpy(tempBuffer, bufPtr, sizeof(message_t));
call AMSend.send(nodeid, &tempBuffer, sizeof(struct));
return bufPtr;
I'm not really sure if this will actually send the modified data
to the required nodeid, but anyway, I still don't know why the
message appears. I'm not even sure if I need tempBuffer in the
first place - can I just send &bufPtr? Any help is very much
appreciated. Thank you.
You're passing &tempBuffer rather than tempBuffer. The former is a
mesage_t**, the latter is a message_t*.
Phil
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