You're pretty much facing a One-Port One-Message limitation.
Hacking MoteIF to do two sends under the covers isn't going
to save you much time. About the only way you could get two
messages to go out, nearly, simultaneously is to ensure that
each sender is running on a separate processor that is not
sharing any resources. What do you consider to be "substantial
time lag/drift/jitter"?
Perhaps if you describe your application requirements we could
be of more help...
MS
Tal Rusak wrote:
Instantiating two MoteIF object appears to work in principle.
However, this will require two calls to send:
moteIF0.send(0, payload);
moteIF1.send(1, payload);
I am not sure if this will introduce substantial time
lag/drift/jitter. Is there any obvious way around this limit? For
example, is it safe to modify the function
synchronized public void send(int moteId, Message m)
on line 145 of MoteIF.java to include two send commands, such as
sender0.send(modeId, m);
sender1.send(modeId, m);
which may introduce less time lag?
Also, is there a way to broadcast a serial packet using this function
(for example, by adding a loop)?
I'm just not if such modifications will disrupt the thread
synchronization in the java programs and/or if it may introduce race
conditions in these programs.
Thanks,
Tal
On Jan 9, 2008, at 9:35 AM, Tal Rusak wrote:
Hi,
I need to use one packet source (i.e., a program sending
packets to
motes over the serial port) to communicate with two SerialForwarders on
two different machines, forwarding the packets generated to both. Is this
possible, and if so, how?
If this is not possible directly, does anyone have a good
workaround?
Just instantiate two MoteIF objects?
Phil
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Platform: WinXP/Cygwin
TinyOS version: 1.x, Boomerang
Programmer: MIB510
Device(s): Mica2, MicaZ, Tmote
Sensor board: homebrew
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