Thank you very much for the reply. I accept your suggestion. I will move my second send() to sendDone().
Thanks again! Lasanthi 2009/6/25 Raffaele Gravina <[email protected]> > Hi, > before sending a message you MUST be sure the previous one has been > completely sent. That means you should move the second call to the command > "send" within the event "sendDone". > > Hope that helps you, > > - Raffaele > > 2009/6/25 ලසන්ති <[email protected]> > >> hi all, >> I am working on a tinyOS project and in my code i have two message >> sendings one after another. My intention is to send both messages every >> time. So, in other words, i want to send the second message every time i >> send the first message. >> But, by looking at the debugging output, it seems to me only one message >> is sent but not the other one; only first message or only second message, >> but not both. >> >> Does anybody have any idea? >> >> I have a second question which is related to this. >> i know that after the first send() method is called, its sendDone() will >> call eventually. So, i was wandering, whether the rest of the receive() >> method is executed or not after the sendDone() is executed? >> >> If it is not, then the answer to my question is obvious. but if it is yes, >> I have no clue. >> >> Thanks! >> >> Lasanthi >> >> >> >> >> >> _______________________________________________ >> Tinyos-help mailing list >> [email protected] >> https://www.millennium.berkeley.edu/cgi-bin/mailman/listinfo/tinyos-help >> > > > > -- > Raffaele Gravina | Research Engineer > > Wireless Sensor Networks Lab Berkeley > 2000 Hearst Ave, suite 304 > Berkeley, CA 94709 > +1 510 666 0174 ext. 101 >
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