Hi, Thanks Dr Omprakash. Actually I was searching a justification to this minus 1. I interpreted this in case of (ne->data_success == 0) to the first transmitted packet for each estimation window. I mean that the first packet in each estimation window is a transmission the others are retransmissions. so the number of retransmission are ne->data_total - 1
Also I interpreted the second one (that seems wrong in the new version) to this equation estETX = ne->data_fail / ne->data_success; = estETX=(ne->data_total - ne->data_success)/ ne->data_success; = estETX=(ne->data_total)/ ne->data_success - 1; // that's why I see that the new version is wrong Am I right? Best regards, Maissa 2010/2/20 Omprakash Gnawali <[email protected]> > On Fri, Feb 19, 2010 at 8:22 AM, Maisa Ben Jamaa > <[email protected]> wrote: > > Hi, > > > > I was wondering why we retrieve 1 at the computation time of estETX? > > > > if (ne->data_success == 0) { > > // if there were no successful packet transmission in the > > // last window, our current estimate is the number of failed > > // transmissions > > estETX = (ne->data_total - 1)* 10; > > } else { > > estETX = (10 * ne->data_total) / ne->data_success - 10; > > ne->data_success = 0; > > ne->data_total = 0; > > } > > You are probably using an older version which computed EETX (ETX-1). I > changed the code to what you see here a few weeks ago. Hopefully this > version is more clear. > > 280 // update data driven ETX > 281 void updateDETX(neighbor_table_entry_t *ne) { > 282 uint16_t estETX; > 283 > 284 if (ne->data_success == 0) { > 285 // if there were no successful packet transmission in the > 286 // last window, our current estimate is the number of failed > 287 // transmissions > 288 estETX = ne->data_total * 10; > 289 } else { > 290 estETX = (10 * ne->data_total) / ne->data_success; > 291 ne->data_success = 0; > 292 ne->data_total = 0; > 293 } > 294 updateETX(ne, estETX); > 295 } > 296 > > - om_p >
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