Hello,
I implement a fuction that send a message. However, the successive call of
this message rend EBUSY. The code is as follows:
My program{
..
while(request_index[gid]>0)
{
//send a join inform message to the GC
send_join_inform(request_node[gid][request_index[gid]], gid);
//sleep(10); faire dormir le capteur inutile
request_index[gid]--;
}
....
}
void send_join_inform(uint16_t nid, uint8_t gid)
{
...
//send the message to GC
//while(radioBusy){printf("waiting...\n");}
res=call AMSend.send(GCAddress[gid], &pkt,
sizeof(riseg_msg_t));
//if(res==SUCCESS) radioBusy=TRUE;
printf("BaseStationP: call AMSend.send(%x, &pkt, len);
return %d TimeStamp: %i\n", GCAddress[gid],res, joinMsgSent->t);
}
I get the following result:
BaseStationP:send a JOIN_INFORM message to the GC of group 1
BaseStationP: call AMSend.send(2, &pkt, len); return 0 TimeStamp: 14
BaseStationP:send a JOIN_INFORM message to the GC of group 1
BaseStationP: call AMSend.send(2, &pkt, len); return 5 TimeStamp: 14
BaseStationP:send a JOIN_INFORM message to the GC of group 1
BaseStationP: call AMSend.send(2, &pkt, len); return 5 TimeStamp: 14
As you note only the first message is sent. For others system return 5 which
means EBUSY.
Did you propose any solution to deal with this problem?
My idea is that, to use a radioBusy variale which is sent to true at each
sent and to false at each sendDone (the commented code). However, with this
solution the system plant at the while(radioBusy){printf("waiting...\n");}
instruction. Some people in this group tell me that the event sendone cannot
interrupt the function that's why the system plant.
How we can make the function interruptable by the senddone event?
Thx for help.
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