Hi An alternative approach is to take advantage of a parameter available with many functions that allows you to specify the minimum number of items that must be present for the computation to occur. Something like the following
compute mean = mean.35(v1 to v40) This would calculate a mean as long as there were 35 or more non-missing values present. Avoids the possible problem of many missing values being substituted for a particular participant. You just need to decide what the minimum is. Best wishes Jim ============================================================================ James M. Clark (204) 786-9757 Department of Psychology (204) 774-4134 Fax University of Winnipeg 4L05D Winnipeg, Manitoba R3B 2E9 [EMAIL PROTECTED] CANADA http://www.uwinnipeg.ca/~clark ============================================================================ --- You are currently subscribed to tips as: [EMAIL PROTECTED] To unsubscribe send a blank email to [EMAIL PROTECTED]
