Hi Annette-
I got this from the following web site:
http://mathforum.org/dr.math/faq/faq.birthdayprob.html
A formula for the probability that *n people* have different birthdays is
((365-1)/365) * ((365-2)/365) * ((365-3)/365) * . . . *
((365-n+1)/365).
If you know permutation notation, you can write this formula as
(365_P_n)/(365^n).
That's the same as
365! / ((365-n)! * 365^n).
[EMAIL PROTECTED] wrote:
>Thanks for all the answers; I'm still wanting to know the 3-person
>probability. In fact, if I take a true 24-hour period, I have FOUR students
>who share a 24-hour slot (three have birthdates on 8-9-89 and one on 8-10-89
>but all within 24 hours of each other!).
>
>Annette
>
>
>Annette Kujawski Taylor, Ph.D.
>Professor of Psychology
>University of San Diego
>5998 Alcala Park
>San Diego, CA 92110
>619-260-4006
>[EMAIL PROTECTED]
>
>---
>
>
--
Don Allen
Department of Psychology
Langara College
Vancouver, B.C., Canada
V5Y 2Z6
604-323-5871
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