On Sun, 05 Nov 2000 13:41:20 -0500 (Eastern Standard Time)
"Kenneth M. Steele" <[EMAIL PROTECTED]> wrote:
>
> Here is one method...
>
> For Person 1, we know a raw score of 22 is due to the mixture of
> C + L. The number of wrong answers was 8. Wrong answers
> represents the case where the testtaker was unlucky. There are
> 4 ways to be wrong on a 5-item question. (This is the
> source of using a correction value of .25) We can calaculate the
> chance of choosing a *wrong* item to estimate the number items
> guessed at and then subtract that estimate of guesses from the
> raw score.
>
> Raw Score Wrong * (1/4) = L Corrected
> 1 22 8 2 20
> 2 26 24 6 20
> 3 32 48 12 20
>
By Guesses at this point, I meant *Lucky* guesses.
Ken
