Cameron Laird-2 wrote:
>
> On Thu, Jul 10, 2008 at 10:35:03PM -0700, Alexnb wrote:
> .
> [hundreds of lines]
> .
> .
>> I am not that familiar with teh after call, but when I change it to this:
>>
>> def Open(root):
>>
>> bb = BusyBar(root, text='Grabbing Definitions')
>> bb.pack(side=LEFT, expand=NO)
>>
>> bb.on()
>> root.update_idletasks()
>>
>> def sleeper():
>> root.update()
>> root.after(100000000, sleeper())
>>
>> sleeper()
>>
>> (notice the () after sleeper in after). It gives me this error.
>> regardless
>> of the number in after. Anyways, I get this error
>>
>> root.update()
>> RuntimeError: maximum recursion depth exceeded
> .
> .
> .
> Alex, I'm lost as to what your current status is--what
> you see as solved, and what questions still remain.
> Do you see why the fragment above is unlikely to make
> you happy? after()'s second argument names a function;,
> it doesn't expect the coder to invoke it. Does the
> self-scheduling in <URL:
> http://tkinter.unpythonic.net/wiki/after > make sense?
> How did it not serve you better to write
>
> root.after(100000000, sleeper)
>
> than what you have above?
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>
>
Well Thats what I said, only, it didn't help. It was for a busy bar and the
bar would stop unless I was using the for loop with the time.sleep() in it.
However, it would always stop at the same spot with after(), but when I used
after(100, sleeper()) vs after(100, sleeper) the sleeper() would still stop,
but it would go a little further down the bar track. If that makes sense.
But I have given up on the idea for now, but thanks for your attempt to
help!
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