Am Donnerstag, Dezember 09, 2010, 13:43:49 schrieb DEXTER MCCONNELL:
> Hi got an error when I used this code
>
> std::ofstream f("result.dat");
> std::copy(it->getBodyBegin(), it->getBodyEnd(),
> std::ostreambuf_iterator<char>(f));
>
> I want to save the uploaded file to disk
>
> How to I fetch the name of the uploaded file?
>
> Thank you
> Dexter
Error? What error? It works for me.
And you get the filename using it->getFilename(). But notice, that it returns a
std::string and the constructor of ofstream needs a const char*. You have to
do something like:
std::ofstream f(it->getFilename().c_str());
And here is a complete example:
----------------------------upload.ecpp
<%pre>
#include <fstream>
</%pre>
<html>
<body>
<form method="post" enctype="multipart/form-data">
<input type="file" name="upload">
<input type="submit">
</form>
<%cpp>
const tnt::Multipart& mp = request.getMultipart();
tnt::Multipart::const_iterator it = mp.find("upload");
if (it != mp.end())
{
log_info("save file to upload/" << it->getFilename());
std::ofstream f(("upload/" + it->getFilename()).c_str());
std::copy(it->getBodyBegin(),
it->getBodyEnd(),
std::ostreambuf_iterator<char>(f));
</%cpp>
<p>
<$ it->getSize() $> bytes received<br>
saved to upload/<$ it->getFilename() $>
</p>
<%cpp>
}
</%cpp>
</body>
</html>
----------------------------
Tommi
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