On 10/01/2014 07:46, "Reyna, David" <[email protected]> wrote:
>Hi Alex, > >Your advice worked! > >View: > tasks = Task.objects.filter(recipe_id = recipe_id).filter(build_id = >build_id) > packages = Package.objects.filter(recipe_id = >recipe_id).filter(build_id = build_id) > >By the way, for the ³task_executed³ member you have this comment in your >model for ³Task², but no ³choices² human-string mappings. Should the GUI >show display > to ³Executed²/³Prebuilt² or what Belen used which was ³Executed²/²Not >executed². We are still evaluating if we will be able to make the changes on how we classify tasks within 1.6. For the moment, showing what the db currently stores (Executed / Prebuilt) will do. Cheers Belén > > task_executed = models.BooleanField(default=False) # True means >Executed, False means Prebuilt > >- David > > >From: Damian, Alexandru [mailto:[email protected]] > >Sent: Wednesday, January 08, 2014 7:40 AM >To: Reyna, David >Cc: [email protected] >Subject: Re: quick question on double key queries > > > >I'd try: > > > tasks = Task.objects.filter(recipe_id = recipe_id).filter(build_id = >build_id) > > > >I suppose the recipe_id and build_id are coming from the frontend through >GET parameters ? > > > >Alex > > > >On Wed, Jan 8, 2014 at 11:17 AM, Reyna, David <[email protected]> >wrote: >Hi Alex, > > > >Perhaps you can answer this easily? I would like to filter the ³Task² >data base for the records that match a given recipe_id. It appears that I >need to filter for both the > FK¹s ³recipe_id² and ³build_id². > > > >How do I set up that query? I do not think that this is correct: > > > >def recipe(request, build_id, recipe_id): > > Š > > tasks = Task.objects.filter(recipe_id=recipe_id, build_id=build_id) > > > >Thanks, > >David > > > > > > > > > > > > >-- >Alex Damian >Yocto Project > >SSG / OTC > > > > > _______________________________________________ toaster mailing list [email protected] https://lists.yoctoproject.org/listinfo/toaster
