The tomcat source codes (URLUtil.java and
SessionUtil.java) may give you some clue.
Weigen
--- Jacob Kjome <[EMAIL PROTECTED]> wrote:
>
> What is the best way to build URL's without
> hardcoding them?
>
> Right now, I have tried this:
>
> SERVLET_HOME = request.getScheme() + "://" +
> request.getServerName() +
> ":" + request.getServerPort() +
> request.getRequestURI();
>
> DOCUMENTS_HOME = request.getScheme() + "://" +
> request.getServerName() +
> ":" + request.getServerPort() +
> request.getContextPath() + "/";
>
>
> This seems to work with a servlet that does posting,
> but I'm confused by
> what is said of getRequestURI() in the servlet API:
>
> *****begin excerpt******
> Returns the part of this request's URL from the
> protocol name up to the
> query string in the first line of the HTTP request.
> For example:
> First line of HTTP request Returned Value
> POST /some/path.html HTTP/1.1 /some/path.html
> GET http://foo.bar/a.html HTTP/1.0
> http://foo.bar/a.html
> HEAD /xyz?a=b HTTP/1.1 /xyz
>
> To reconstruct an URL with a scheme and host, use
>
HttpUtils.getRequestURL(javax.servlet.http.HttpServletRequest).
>
> Returns:
> a String containing the part of the URL from the
> protocol name up to the
> query string
> *****end excerpt*******
>
>
> It seems to say that it should return the whole
> path, whereas I am
> already specifying that from the scheme all the way
> up to the server
> port. I need to get the the context + path info
> (such as /servlet/) and
> the actual servlet.
>
> Another problem with what I'm doing is that
> getContextPath() does not
> exist in the servlet 2.1 API.
>
>
> So, what is the best generic (and most proper) way
> to get what I'm
> trying to achieve?
>
>
> thanks,
>
> Jake
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