You can use: ":" + request.getServerPort()
jake
-----Original Message-----
From: MK [mailto:[EMAIL PROTECTED]]
Sent: Monday, December 18, 2000 2:58 PM
To: [EMAIL PROTECTED]
Subject: link problem
I have a problem which breaks my head :-)
I am using Tomcat 3.2.1.
Here is what I have in server.xml
<Host name="127.0.0.1" >
<Context path="/exchange"
docBase="D:/GuidanceExchange/exchange"
crossContext="false"
debug="0"
reloadable="true" >
</Context>
</Host>
I have two pages one is located:
D:\GuidanceExchange\exchange\index.jsp
and have a link <a href="<%= request.getContextPath() %>"/jsp/test.jsp">
test</a>
test.jsp is another page located at
D:\GuidanceExchange\exchange\jsp\test.jsp
The problem is when I execute index.jsp page the link is pointing to
http:///exchange/jsp/test.jsp <http:///exchange/jsp/test.jsp> which is
incorrect...it should point to
http://127.0.0.1:8080/exchange/jsp/test.jsp
<http://127.0.0.1:8080/exchange/jsp/test.jsp> . So, how do I get
127.0.0.1:8080 into my URL?
Thank you very much for any help in advance,
Maksim.
