According to RUNNING.txt, "you can pass a
"-Dcatalina.base=$CATALINA_BASE" argument when
executing the startup command" to run a specified configuration. Yet
when I try I get this:
C:\jakarta-tomcat-5.0.16\bin>startup
-Dcatalina.base=c:\jakarta-tomcat-5.0.16\secure
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CATALINA_TMPDIR: ..\temp
Using JAVA_HOME: c:\jdk1.4.2
usage: java org.apache.catalina.startup.Catalina [ -config {pathname} ]
[ -debug ] [ -nonaming ] { s
tart | stop }
and it just runs the default configuration. I have found I can do this
to run a specified configuration (in a startup-secure.bat batch file
under Win2K):
setlocal
set CATALINA_BASE=C:\jakarta-tomcat-5.0.16\secure
call startup -security
I looked in catalina.bat, and it looks like it pulls CATALINA_BASE only
out of the environment, so I can't see how passing it startup.bat will
accomplish the desired goal.
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