In web.xml:
<web-app>
<servlet>
<servlet-name>digfidl</servlet-name>
<servlet-class>se.two4hr.servlet.DLServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>digfidl</servlet-name>
<url-pattern>/digfidl</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>digfidl</servlet-name>
<url-pattern>/digfidl/*</url-pattern>
</servlet-mapping>
</web-app>
-----Original Message-----
From: matsmobil [mailto:[EMAIL PROTECTED]
Sent: 23 January 2004 13:25
To: [EMAIL PROTECTED]
Subject: Special URL servlet request.
This request works:http://digfi.com/digfidl/digfidl and calls my Servlet OK.
The question is how can I call my servlet with the following URL:
http://digfi.com/digfidl/digfidl/dAc/OM1617RbR/YT4075/Uk5673We/qih/dFOE1051/
1gpus/LYxx/tKG0/iXcaP.rm"/>?copyright="digfi.com"&author="Chine
& The Slippery Horns"&title="Scatterminded"
I have to make this request like this because my calling applikation can't
use '?' in the URL-requests.
Could this be done in TC 5.0.18 only ore do I have to have apache as
frontend for
TC 5.0.18.
---------------------
In TC/conf/server.xml I have added the following row:
<Context path="/digfidl" docBase="digfidl" debug="0" reloadable="true" />
---------------------
TC/webapps/digfidl/WEB-INF/web.xml contains:
<web-app>
-
<servlet>
<servlet-name>digfidl</servlet-name>
<servlet-class>se.two4hr.servlet.DLServlet</servlet-class>
</servlet>
-
<servlet-mapping>
<servlet-name>digfidl</servlet-name>
<url-pattern>/digfidl</url-pattern>
</servlet-mapping>
</web-app>
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