On Thu, 25 Nov 2004 06:21:52 -0800 (PST), Chirag <[EMAIL PROTECTED]> wrote: > Software Installed > -------------------------- > > jakarta-tomcat-5.5.2 > JDK 1.5 > IE 6.0SP1 > > Requirement > -------------------- > > The PC has Internet Connection. and we start the > Tomcat Server. > > After that we try to see the site > http://localhost:8080/ > > We get normal Tomcat Home Page ready > > Afterwards I try to surf the same site by typing > > http://160.160.160.160:8080/ > > where > > 160.160.160.160 is the IP address > > After that the Tomcat Server throws the error and the > IE also is trying to display the page > > The problem is that I want that other people should be > able to access my site through IP Address and I don't > want to get into the domain thing > > How to do that > > Exception Raised in Tomcot Server > > INFO: Server startup in 20650 ms > Nov 18, 2004 8:03:23 PM > org.apache.tomcat.util.net.PoolTcpEndpoint > acceptSocket > SEVERE: Endpoint > ServerSocket[addr=0.0.0.0/0.0.0.0,port=0,localport=8080] > ignored exception: java.net.SocketException: socket > closed > java.net.SocketException: socket closed > at > java.net.PlainSocketImpl.socketAccept(Native Method)
I don't understand everything in wour email. If you get an exception during a socket accept, then it means trouble. -- xxxxxxxxxxxxxxxxxxxxxxxxx Rémy Maucherat Developer & Consultant JBoss Group (Europe) SàRL xxxxxxxxxxxxxxxxxxxxxxxxx --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
