Brereton, Stephen wrote:
how exactly does the servlet get called? Are you using the web server?
-----Original Message-----
From: teknokrat [mailto:[EMAIL PROTECTED]
Sent: 13 June 2005 18:44
To: [email protected]
Subject: Re: can anyone make sense of this
Brereton, Stephen wrote:
That's just your Tomcat service running. It does take a few moments to get
started - that's just Java getting going. If your task manager isn't
running
to show 'all users', you might well not see the service running
-----Original Message-----
From: teknokrat [mailto:[EMAIL PROTECTED]
Sent: 13 June 2005 17:52
To: [email protected]
Subject: can anyone make sense of this
I have the latest tomcat 5.0 installed on windows server 2003 with java
5. I run startup.bat and call a servlet that hits a jboss instance
remotely. Looking through the connection events with TDIMon ( from
www.sysinternals.com ) I notice that a process tomcat5.exe sends a UDP
datagram on port 137 to the remote server just before creating the TCP
connection. Now, what I don't understand is
1. All the other network events are created by the process java.exe. I
am not running any tomcat.exe - in fact I have deleted them. There is no
tomcat5.exe process in the task manager so what is going on here.
2. this is a very slow. tomcat5.exe makes about three udp datagrams and
takes about 2 seconds.
3. I realise that this may be a jboss issue but if anyone can confirm ro
deny this I would appreciate this
thanks
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Thats what I thought. But i am not running the service, only using
startup.bat. Also I have renamed the tomcat5.exe. In the task manager I
have show processes for all users enabled.
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Thanks but the issue is resolved now. Apparently, make sure netbios is
disabled!
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