First, I assume you mean CLASSPATH and /lib, or PATH and /bin, but not CLASSPATH
and /bin?
Second, your situation has me puzzled. Mark's answer appears correct, as
"unknown protocol: c" is typically the "C:\" of a Windows filesystem path. And
checking the documentation, StreamSource requires a URI, so a windows filesystem
path won't work.
However...my code does something very similar, and it works. The only difference
is that I'm doing it for a StreamResult, not a StreamSource:
String root = getServletContext().getRealPath("");
String xmlFileName = root + File.separator + "WEB-INF" +
File.separator + "TestData.xml";
TransformerFactory.newInstance().newTransformer().transform(
new DOMSource(buffer),
new StreamResult(xmlFileName)); // DOM into XML
I just threw in a quick println(), and "xmlFileName" is equal to
"C:\tomcat-5.0.19\webapps\TestApp\WEB-INF\TestData.xml".
Can anyone explain why mine works and Franklin's fails? Maybe I'm missing
something obvious.
Jay
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-----Original Message-----
From: Mark Thomas [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 25, 2005 4:21 PM
To: Tomcat Users List
Subject: Re: Malformed URL Exception: unknown protocol: c
I assume becuase the url you pass it starts c:\ as that is the start
of the XML_WORK_PATH. You need to prefix it with file:/// (or however
many slashes you need to get this to work in windows).
Mark
Franklin Phan wrote:
> I use Windows XP Pro. My JAVA_HOME environment variable points to
> c:\j2sdk1.4.2_05. The CLASSPATH is set to have as the first element
> "%JAVA_HOME%\bin". I've written an XSL Transform servlet that makes use
> of the package javax.xml.transform. Why do I get the following error:
>
> javax.servlet.ServletException:
> javax.xml.transform.TransformerConfigurationException:
> javax.xml.transform.TransformerException:
> java.net.MalformedURLException: unknown protocol: c
>
> The four lines above actually appear altogether in one line. And the
> error appears to be due to the following piece of code where I'm trying
> to get the path to a folder on the local drive to access a file:
>
> String XML_WORK_PATH = "/WEB-INF/work_xml";
> TransformerFactory tFactory = TransformerFactory.newInstance();
> Transformer transformer =
> tFactory.newTransformer(new
>
javax.xml.transform.stream.StreamSource(getServletContext().getRealPath(XML_WORK_PATH)
> + "\\" + xslParam)); //xslParam is an XSL file name
>
>
> The Malformed URL Exception does not occur on another machine running
> Windows XP Server.
>
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