could you tell me more how to make a filter?
are you meaning init-parameter in web.xml?
inorder to call getRealPath("/"), I think I must have
a request. anyway I can get the path(context) name
during servlet init() stage?
thanks again.
--- Deacon Marcus <[EMAIL PROTECTED]> wrote:
> Hi,
> Depends on what exactly you need. You could use
> .getRealPath("/") to get a
> String like "/tomcat/webapps/my-web-app/", then you
> can parse it to isolate
> the "my-web-app" part.
> Personally, I use a Filter (but load-on-webapp-init
> Servlet will do) that
> takes a parameter like "webapp=webapp.com" and
> stores it in application
> (ServletContext) scope so it's available to any
> Servlet/JSP.
>
> Greetings, deacon Marcus
>
> > -----Original Message-----
> > From: chiuming [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, October 02, 2001 3:19 AM
> > To: [EMAIL PROTECTED]
> > Subject: get Servlet Context Name
> >
> >
> > hi,
> > any way I can get a servlet context ( web
> application
> > )'s name with in a servlet? on Servlet API 2.2
> (not
> > Servlet 2.3)
> >
> > -OR- there is no way to do that?
> >
> > P.S. I am using tomcat... may I access internal
> tomcat
> > object to achieve that?
> >
> > thanks
> >
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