Hi guys,
the following piece of code from the web.xml file always gives me
"Apache Tomcat/4.0.1-HTTP Status 404 - /chat/servlet/ChatAdminServlet"
error
when I run it on Linux and (?!) works fine on Windows
How can I fix it ? Can anyone give me advice how can I make it work on
Linux?
Thanks in advance
Roman Mikhailov
***********************
<context-param>
<param-name>ADMIN_PATH</param-name>
<param-value>/chat/servlet/ChatAdminServlet</param-value>
</context-param>
<context-param>
<param-name>LISTROOMS_PATH</param-name>
<param-value>/chat/servlet/ListRoomsServlet</param-value>
</context-param>
<context-param>
<param-name>CHATROOM_PATH</param-name>
<param-value>/chat/servlet/ChatRoomServlet</param-value>
</context-param>
******************
ChatAdminServlet.class
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
public class ChatAdminServlet extends HttpServlet {
String chatRoomPath;
String listRoomsPath;
String chatAdminPath;
public void init() {
ServletContext context = getServletContext();
------->>> I guess it breaks somewhere here
chatRoomPath = context.getInitParameter("CHATROOM_PATH");
listRoomsPath = context.getInitParameter("LISTROOMS_PATH");
chatAdminPath = context.getInitParameter("ADMIN_PATH");
}
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