Hello,
I work with Tomcat 4.0 and I'd like to set a context-param in my web.xml
file of my web application.
So I do this :
<web-app>
<servlet>
<servlet-name>add</servlet-name>
<servlet-class>AddServlet</servlet-class
</servlet>
<context-param>
<param-name>logFile</param-name>
<param-value>c:/jakarta-tomcat-4.0.1/webapps/myWebapps/file</param-value>
</context-param>
<error-page>
<exception-type>javax.servlet.UnavailableException</exception-type>
<location> /unavailable.html </location>
</error-page>
</web-app>
But when I declare my context-param and then when I restart my server, I
have a SAXException whitch explain me that the web.xml file is not correct.
Can anyone help me please?
thanks.
Aline
WEBCASTER
T +33 (0)3 28 36 25 25
F +33 (0)3 20 13 06 04
http://www.oeilpouroeil.fr
http://www.visiodrome.com
--
To unsubscribe: <mailto:[EMAIL PROTECTED]>
For additional commands: <mailto:[EMAIL PROTECTED]>
Troubles with the list: <mailto:[EMAIL PROTECTED]>
