I am still a bit confused. I do not know what the servlet-name and servlet-class are
referring
to?
The Jsp Page it called TopNav.jsp and the bean is called PictureBrowserBean. I want
to have the
bean PictureBrowserBean be able to access the extra parameter. In this case, the
location of the
properties file. Here i my guess at what I would do
<servlet>
<servlet-name>TopNav</servlet-name>
<servlet-class>PictureBrowserBean</servlet-class>
<init-param>
<param-name>propFile</param-name>
<param-value>/opt/jakarta-tomcat-4.0.3/webapps/trips-dev</param-value>
</init-param>
</servlet>
Is this correct? I am going to try this, but I am a bit short on time right now.
Thanks again
for your help.
Adam
--- Subir Sengupta <[EMAIL PROTECTED]> wrote:
> You can do something like this in your web.xml
>
> <servlet>
> <servlet-name>somename</servlet-name>
> <servlet-class>someclass</servlet-class>
> <init-param>
> <param-name>param1</param-name>
> <param-value>somevalue</param-value>
> </init-param>
> </servlet>
>
> You can then call getServletConfig().getInitParameter("param1") from the
> init method of the somename servlet.
>
> Hope this helps,
> Subir
>
> -----Original Message-----
> From: Adam Pfeiffer [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, June 04, 2002 10:52 PM
> To: [EMAIL PROTECTED]
> Subject: How to load properties into tomcat 4.0.3?
>
>
> Hello,
> I have a bean that uses the Properties Object. Currently, on each jsp that
> calls that bean I have
> to do a bean.setPropsDir() which sets the directory where to find the
> properties file. Is there a
> way in server.xml, web.xml or some other way that I can put in a variable
> that will define the
> directory where the properites file exists so that the class can access
> this?
>
> Thanks.
>
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