Hi Kyle
Run the following code in your servlet.
ServletContext sc = getServletContext();
String RootPath = sc.getRealPath("/");
This will return the path where the context is. Ie:
$TOMCAT_HOME/webapps/yourapp
This will work in all situations no matter where your app is installed
Hope this helps
Donie
-----Original Message-----
From: Pearsall, Kyle [mailto:[EMAIL PROTECTED]]
Sent: 10 July 2002 18:32
To: Tomcat (E-mail)
Subject: PATH issue
I have set up Tomcat with an addition to the PATH in startup.bat ("set
PATH=..\webapps\TestServlet\dll;%PATH%"). When Tomcat starts from this
batch file, the servlet can access files in this directory. However, when
Tomcat runs as a service, the servlet can't access the files in this
directory. Tomcat produces javax.servlet.ServletException and
java.lang.UnsatisfiedLinkError messages. It seems the NT Tomcat service
bypasses startup.bat.
How can I set up the NT service to load the PATH statement above? Is this
possible? Considering the nature of the product, I can't update the path
manually in the Windows environment variables (although this does work).
And I would like to keep the files inside the servlet, and not in the
Tomcat\bin directory (I tried this and it works as well).
What can I do?
Thank you in advance for your help.
Kyle Pearsall
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