Have you defined the resource itself in server.xml? You'll need to set up
the appropriate <Resource> and <ResourceParams> elements there in order to
define how Tomcat is actually supposed to create the object factory for
this resource. See the jndi-resources-howto.html for more information on
creating object factories for your own beans.
Craig
On Sat, 27 Jul 2002, Michael Delamere wrote:
> Date: Sat, 27 Jul 2002 16:10:44 +0200
> From: Michael Delamere <[EMAIL PROTECTED]>
> Reply-To: Tomcat Users List <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED]
> Subject: Tomcat + JNDI
>
> Hi,
>
> I�m trying to access a bean via JNDI using Tomcat. Unfortunately, reading
> documentation and mailing-lists hasn�t helped me very much. Could someone
> please expalin to me what is involved in accessing a bean in tomcat via
> JNDI. Here�s what I�ve done so far:
>
> ========== WEB.XML ====================
> <resource-env-ref>
> <description>
> Object factory for MyBean instances.
> </description>
> <resource-env-ref-name>
> jdo/FindMe
> </resource-env-ref-name>
> <resource-env-ref-type>
> com.test.osforum.services.FindMe
> </resource-env-ref-type>
> </resource-env-ref>
>
> ======== MY ACTION SERVLET ============
> Context context;
> Context envCtx;
> try {
> context = new InitialContext();
> envCtx = (Context) context.lookup("java:comp/env");
>
> FindMe findme = (FindMe) envCtx.lookup("jdo/FindMe");
> message = findme.getSillyMessage();
> request.setAttribute("message", message);
> } catch (NamingException e) {
> System.out.println("-----| CATCH NAMING EXCEPTION-: " + e.toString() + "
> |----- \n\n");
> e.printStackTrace();
> }
> ========================================
>
> The above results in a " javax.naming.NamingException: Cannot create
> resource instance". Could someone please point me in the right direction.
>
> Regards,
>
> Michael
>
>
>
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