Well, so far you've asked two different questions, yet they are supposed to be the same.
Your first post wanted an IP address from a name, getByName() will do that for you, assuming by "name" you mean fully-qualified internet domain name. Now you are saying that the IP address will actually be in the URL, in which case you don't need to look it up, so it's not clear what you are trying to do. If you need to differentiate content based on whether someone accesses a resource by IP address or name, and there are many possible IP addresses, then all you have to do is test if the value returned from getRequestURI() has an IP address in it. So rather than look for a specific IP address, all you have to do is look for ANY IP address. That will tell you if someone entered the machine name or not. If you need something to translate a Microsoft WINS name (server name) to an IP address, you'll need some sort of Java WINS library...check google...my guess is the SAMBA group has written one (http://www.samba.org) but it may not be generally available. John Turner [EMAIL PROTECTED] -----Original Message----- From: Jose Francisco Junior [mailto:[EMAIL PROTECTED]] Sent: Friday, August 09, 2002 2:55 PM To: Tomcat Users List Subject: Converting HOST to IP an IP to HOST All right, but it does not solve my problem. I did a local web system that can be accessed both by IP or HOST. Depending on the way the user accessed( by HOST or IP ) the application I must display different contents. I could do this: if( request.getRequestURL().toString().equals("192.168.20.10") ) out.print("show IP content"); else ou.print("show HOST content"); But the web server has many network devices and the user can accesss the system from many other IP and HOSTs. The InetAddress.getByName() does not work with the machine network name only with inet hosts. Does anybody has any idea ??? Thanks in advice, Junior On Fri, 9 Aug 2002 13:50:59 -0400 "Turner, John" <[EMAIL PROTECTED]> wrote: > >Come on...RTFM: > >java.net.InetAddress.getByName(); > >Sheesh. > >John Turner >[EMAIL PROTECTED] > > >-----Original Message----- >From: Jose Francisco Junior [mailto:[EMAIL PROTECTED]] >Sent: Friday, August 09, 2002 1:44 PM >To: Tomcat Users List >Subject: Re: Configuration for High TPS > > >Please, > >I know it is a bit off-topic but I am trying to get a IP > address from an URL like this: >new URL("http://java.sun.com";); //this is the URL > >How can I get the IP address from this URL? Any idea ?? > > >Thanks in advance, >Junior >________________________________________________ >Don't E-Mail, ZipMail! http://www.zipmail.com/ > >-- >To unsubscribe, e-mail: ><mailto:[EMAIL PROTECTED]> >For additional commands, e-mail: ><mailto:[EMAIL PROTECTED]> > >-- >To unsubscribe, e-mail: > <mailto:[EMAIL PROTECTED]> >For additional commands, e-mail: > <mailto:[EMAIL PROTECTED]> > ----------------------------------------- Prefiro as l�grimas da derrota do que a vergonha de n�o ter lutado... Willan Brook ----------------------------------------- ________________________________________________ Don't E-Mail, ZipMail! http://www.zipmail.com/ -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]> -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>
