Re: How to connect to a Data-File above the WEB-INF-Folder from aservlet????

[Patrick Kosiol]

Howdy ;-)

thx 4 ur help, this it is what I wanted.

But there is also another Question. I have a ".exe-file" that I want to start out of the servlet. Of course with some paramteters and one of my data-files as one of the parameters. Is that possible? And how do I do that?
If that works and the .exe-file is accessing my data-file and another instance of the servlet does the same the tomcat can be crash or the servlet or so. How do I handle that?

Patrick

Shapira, Yoav wrote:

Howdy,

How do I connect to a Data-File above the WEB-INF-Folder from a

servlet????

For example my class is placed in
$CATALINA_HOME/webapps/ROOT/WEB-INF/classes/myApp/server/servlet.class
and my data-files are placed in $CATALINA_HOME/webapps/data/data.dat or
so. Is this possible or does anybody know a better way to place my
data-files? And how do I connect to them?

Data files belonging to or referenced by your webapp should be under
your webapp's structure (or within your webapps .war file). So if your
app is in the ROOT context, your data files should be in
$CATALINA_HOME/webapps/ROOT/data/data.dat.

Then, from your servlets, you could do:

InputStream is =
getServletContext().getResourceAsStream("/data/data.dat");
(and do whatever you need with the input stream, e.g. read it)
or
URL fileUrl = getServletContext().getResource("/data/data.dat");
To just get the URL for the file. Don't assume this is a file:// or an
http:// URL. It may be a jndi:/localhost/... type of URL as well.

You could also use String filePath = getServletContext().getRealPath("/data/data.dat");
approach, but that won't work if you're deploying out of a .war file.

Finally, if for some reason you cannot place your data files under your
own context, you can set a data file directory as a context parameter in
your web.xml. For example:
<context-param>
<param-name>dataFileDirectory</param-name>
<param-value>/home/myname/mydatafiles</param-value>
</context-param>

Then in your servlets, you could do:
String dataFileDirectory =
getServletContext().getInitParameter("dataFileDirectory");

String filePath = dataFileDirectory + File.separator + "data.dat";
And go from there.

I hope you find this helpful,

Yoav Shapira
Millennium ChemInformatics

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