Hello and thank you for the reply. That sort of helped...I'm able to
get the correct results from that query that I posted earlier, but the
problem is that I don't know how to actually change the string field
to a date field. Honestly, I'm not too familiar with TopBraid and
SPARQL, but I figure that this would be a good way to learn.

As for the "Converting a string to a class", my explanation was rather
poor. I'll try to use an example. Say I have a collection of surveys
that are instances of class "Survey". These surveys have names or ID
numbers on them (some unique identifier) and I want to use the surveys
to populate the class "Person". Hopefully that makes sense.

Thank you for any and all help.


On 1/22/09, Holger Knublauch <[email protected]> wrote:
>
> Hi Joseph,
>
> BTW SPARQL has a built-in feature to convert between XSD datatypes, e.g.
>
>       LET (?string := "2008-01-02") .
>       LET (?date := xsd:date(?string))
>
> binds ?date with "2008-01-02"^^xsd:date.
>
> I don't know what you mean with converting a date to a class, but you
> can convert a URI string to a class using the function smf:resource(?
> uri). You could then use smf:buildURI() to construct a valid URI from
> a date.
>
> I hope that helps, if not please clarify.
>
> Holger
>
>
>
> On Jan 22, 2009, at 6:45 AM, Joseph Shea wrote:
>
>>
>> Hello all. I'm relatively new to TopBraid. I'm trying to convert
>> strings into classes, or even dates for that matter....I'm not really
>> sure how to do that, but I tried converting a string into a date, and
>> the following SPARQL query seemed to have done the job, though it was
>> never changed. Any advice on this, or how to convert strings into
>> classes? (Websites and tutorials would also be appreciated)
>>
>> SELECT  *
>>      WHERE {
>>              ?person :HasBirthdate ?Birthdate .
>>              LET (?newBirthdate := smf:cast(?Birthdate, xsd:date)) .
>>      }
>>
>> >
>
>
> >
>

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