thanks :) On Jan 13, 3:49 am, Holger Knublauch <[email protected]> wrote: > Hi Andrew, > > under certain conditions you could solve this with a recursive SPIN function. > Assuming you have a way of accessing the sub-strings with an index, then you > could define a function that takes the index and the partial solution as > arguments, and then recursively calls itself (with index + 1) until it has > reached the end of the list, accumulating the results with fn:concat in each > recursion. > > So roughly: > > SPIN function my:strConcat > Arguments: ?list, ?index, ?base > body: > > SELECT ?result > WHERE { > ?list my:member ( ?element ?index ) . > LET (?c := fn:concat(?base, ?element)) . > LET (?result := my:strConcat(?list, ?index + 1, ?c) > } > > This requires though that the results are available in some triple form so > that you can walk the results (here: using a magic property my:member). [This > would work with magic SPIN properties if SPARQL would allow to place > variables in the OFFSET clause, but unfortunately it doesn't]. > > Otherwise, I also see SPARQLMotion as the only option, because it provides > iteration modules and is - unlike SPARQL - stateful. > > Regards, > Holger > > On Jan 12, 2010, at 11:25 AM, AndrewB wrote: > > > > > if i have a result set > > > a,bz > > a,ha > > > Can I concatenate it into > > > a,bzha ? > > > Maybe using spin? > > > Thanks! > > > -Andrew > > -- > > You received this message because you are subscribed to the Google Groups > > "TopBraid Composer Users" group. > > To post to this group, send email to > > [email protected]. > > To unsubscribe from this group, send email to > > [email protected]. > > For more options, visit this group > > athttp://groups.google.com/group/topbraid-composer-users?hl=en.
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