Alison; I'd suggest writing a SPIN function for this. The function
would be a subclass of spin:Functions, let's call it :mySum. It would
define one argument (spin:constraint). Let's call that ?arg1 for
now. The body of the query would be:
SELECT (SUM(?value) AS ?return)
WHERE
{ ?arg1 example:has_part ?value
}
You can then call it in any SPARQL query. In your case, you'd pass
example:resource to it, or if in a SPIN rule, I'd expect you want ?
this:
BIND(:mySum(?this) AS ?sum)
Note you can easily generalize the function to also take a property as
a second argument, then pass example:has_part or whatever to it.
The SPIN page has an example of a SPIN function - see Documentation in
http://www.topquadrant.com/products/SPIN.html. And the tutorial has a
pretty good section on SPIN functions - see Documentation on the RHS
of the SPIN page..
-- Scott
On Sep 9, 3:42 pm, Alison Callahan <[email protected]> wrote:
> Hello all,
>
> I would like to write a spin:rule that sums integers connected with a
> resource and then connects the sum to the resource. For example, if a
> resource exists such that
>
> example:resource example:has_part "1"^^xsd:integer
> example:resource example:has_part "2"^^xsd:integer
>
> Is it possible to write a spin:rule that would take these numbers, sum them
> and assert
>
> example:resource example:has_sum_value "3"^^xsd:integer
>
> This seems like it would be relatively straightforward, but I don't know to
> handle a case in which it is not known beforehand how many numbers there are
> to be summed.
>
> Any help is appreciated, thanks,
>
> Alison
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