Hi again Scott, Please see my follow-up question below.
Thanks. On Thu, May 9, 2013 at 2:26 PM, Scott Henninger <[email protected]> wrote: > Allison; Since the AnotherExample:ScoreAttendedCollege returns one value, > not a set of values (multiple rows) or a list of values (multiple > columns), then the best choice is to use a SPIN function. Change the > type of :ScoreAttendedCollege to spin:Functions and use in a BIND or > projection: > > SELECT ?score > WHERE { > BIND(AnotherExample:ScoreCollege("John") AS ?score). > } > > ...and the projection version would be as follows: > > > SELECT (AnotherExample:ScoreCollege("John") AS ?score) > WHERE {} > > These translate into the exact same SPARQL algebra, so it's a matter of > preference which one you use. > > Because kennedys:JohnKennedy has kennedys:almaMater more than one college, is it not correct that making AnotherExample:ScoreCollege a spin:function and not magic property would mean that only one of the colleges he attended would be evaluated and its score returned? How could one, for example, have a function evaluate all colleges he attended and return the maximum value and the associated college? Apologies for the very specific example, but this is really the behaviour I'm going after. > For your magic property, I think you just got it backwards the subject of > the magic property are the variables bound in the WHERE clause. The > object are the selected variables. So I think the following will work: > > SELECT * > WHERE { > ("John") AnotherExample:ScoreCollege (?score) . > } > > Yes, I had it backwards. This worked. On Wed, May 15, 2013 at 3:37 PM, Alison Callahan <[email protected]>wrote: > Hi again Scott, > > Please see my follow-up question below. > > Thanks. > On Thu, May 9, 2013 at 2:26 PM, Scott Henninger < > [email protected]> wrote: > >> Allison; Since the AnotherExample:ScoreAttendedCollege returns one >> value, not a set of values (multiple rows) or a list of values (multiple >> columns), then the best choice is to use a SPIN function. Change the >> type of :ScoreAttendedCollege to spin:Functions and use in a BIND or >> projection: >> >> SELECT ?score >> WHERE { >> BIND(AnotherExample:ScoreCollege("John") AS ?score). >> } >> >> ...and the projection version would be as follows: >> >> >> SELECT (AnotherExample:ScoreCollege("John") AS ?score) >> WHERE {} >> >> These translate into the exact same SPARQL algebra, so it's a matter of >> preference which one you use. >> >> > Because John Kennedy attended multiple colleges, is it not correct that > making AnotherExample:ScoreCollege a spin:function and not magic property > would mean that only one of the colleges he attended would be evaluated and > its score returned? How could I, for example, have a function evaluate all > colleges he attended and return the maximum value and the associated > college? I apologize for the very specific example, but this is really the > behaviour I'm going after. > > >> For your magic property, I think you just got it backwards the subject >> of the magic property are the variables bound in the WHERE clause. The >> object are the selected variables. So I think the following will work: >> >> SELECT * >> WHERE { >> ("John") AnotherExample:ScoreCollege (?score) . >> } >> >> > Yes, I had it backwards. This worked. > >> -- Scott >> >> On 5/9/2013 10:42 AM, Alison Callahan wrote: >> >> Hi Scott, >> >> Thanks for your detailed reply. I successfully followed your >> MagicExample:FindNamesOfCollegeGrad example. >> >> I have a follow-up question, based on another >> thread<http://mail-archive.com/[email protected]/msg02089.html>: >> If I use a magic property in the spin:body of another magic property, and >> there is more than one result when the magic property is executed, how can >> I retrieve all of the results? >> >> For example, when John Kennedy is passed in to the >> FindNamesOfCollegeGrad magic property in a SPARQL query, i.e. >> >> SELECT * >> WHERE >> { ?person a kennedys:Person . >> ?person kennedys:almaMater ?college . >> (?person ?college) MagicExample:FindNamesOfCollegeGrad ("John" >> ?middle ?last) >> } >> >> there are two results for ?college: kennedys:Harvard and >> kennedys:Princeton. >> >> Now let's say I have another magic property called >> 'AnotherExample:ScoreAttendedCollege' where a first name is passed in as >> ?arg1 and the spin:body of the property is: >> >> SELECT ?collegeScore >> WHERE >> { >> (?person ?college) MagicExample:FindNamesOfCollegeGrad (?arg1 ?middle >> ?last) . >> BIND(IF((?college = kennedys:Princeton), 1, 0) AS ?collegeScore) . >> } >> >> In other words, if the person with the specified first name attended >> Princeton, return a score of 1, else return a score of 0. >> >> I created this magic property, but when I use it in a SPARQL query as >> follows: >> >> SELECT * >> WHERE { >> (?score) AnotherExample:ScoreCollege("John") . >> } >> >> there are no results. However, if I use it in a SPARQL query this way: >> >> SELECT ?score >> WHERE { >> BIND(AnotherExample:ScoreCollege("John") AS ?score). >> } >> >> the result of the query is 0. My hunch is that this is because only the >> first bound result (kennedys:Harvard) was evaluated by the >> 'AnotherExample:ScoreCollege' magic property, i.e. the kennedys:Princeton >> result is never evaluated because the iteration seems to break. Is this >> correct? >> >> How can I use AnotherExample:ScoreCollege to return the score for each >> value bound to the ?college variable returned by the >> MagicExample:FindNameOfCollegeGrad >> magic property? If I can't use BIND within a magic property to assign a >> value based on the result of an embedded magic property, what alternatives >> exist? >> >> Thanks again! >> >> Alison >> >> >> On Wed, May 8, 2013 at 4:11 PM, Scott Henninger < >> [email protected]> wrote: >> >>> Allison, probably the best way to learn magic properties is by >>> example. In the Composer navigator, go to >>> TopBraid/Examples/kennedysSPINMagic.ttl and open that. >>> >>> In the Classes view find spin:MagicProperties. A Magic property is a >>> subclass of spin:MagicProperties. You can see the body of the >>> definition for age (after running inferences), grandfather, and >>> grandMother. These are used in SPARQL as a property that instead calls >>> the body of the query (hence a "magic" property). >>> >>> An example, let's say you want to find a grandfather: >>> SELECT * >>> WHERE >>> { ?person a kennedys:Person . >>> ?person kspin:grandFather ?gf >>> } >>> >>> Note you can use this magic property either way. So to find all >>> grandchildren of Joe Kennedy: >>> SELECT * >>> WHERE >>> { ?gchild kspin:grandFather kennedys:JosephKennedy >>> } >>> >>> I know, I haven't answered the question yet. For multiple parameters of >>> values, use a list structure (see, for example top:files in Help > >>> TopBraid Composer > Reference > SPARQL Property Functions). As an >>> additional example, I've added an example in the attached file to >>> define a magic property named MagicExample:FindNamesOfCollegeGrad >>> (kinda a silly example, buyt it gets the idea across) >>> >>> You can use it this way for example: >>> >>> SELECT * >>> WHERE >>> { ?person a kennedys:Person . >>> ?person kennedys:almaMater ?college . >>> (?person ?college) MagicExample:FindParentsOfCollegeGrad (?first >>> ?middle ?last) >>> } >>> >>> You can bind/not bind any of the input parameters or output values. For >>> example to find all John's try this. >>> >>> SELECT * >>> WHERE >>> { ?person a kennedys:Person . >>> ?person kennedys:almaMater ?college . >>> (?person ?college) MagicExample:FindParentsOfCollegeGrad ("John" >>> ?middle ?last) >>> } >>> >>> Given that as an interesting example to explore, let us know if that answers >>> the question or if you have follows. >>> >>> -- Scott >>> >>> On 5/8/2013 11:51 AM, Alison Callahan wrote: >>> >>> Hi Holger, >>> >>> I have looked at Magic Properties, and thought they were relevant to >>> my question, but I couldn't find any examples of how to create a magic >>> property that returns multiple values. On the page you linked to, it >>> says "Magic properties can also take multiple arguments and result values >>> using a (rather obscure) list syntax - these cases are technically >>> supported but complex to represent in the SPIN RDF syntax". >>> >>> Could you provide more detail or a link that describes this list >>> syntax for creating a magic property that returns multiple values? >>> >>> Thanks! >>> >>> Alison >>> >>> >>> On Mon, Apr 29, 2013 at 7:00 PM, Holger Knublauch < >>> [email protected]> wrote: >>> >>>> Hi Allison, >>>> >>>> yes take a look at Magic Properties >>>> >>>> http://spinrdf.org/spin.html#spin-magic >>>> >>>> These may not only return multiple "rows" but also multiple variables >>>> per row. >>>> >>>> Please take a look at the online material and get back to us if you >>>> have specific follow-up questions. >>>> >>>> HTH >>>> Holger >>>> >>>> >>>> >>>> On 4/30/2013 1:01, Alison Callahan wrote: >>>> >>>>> Hello all, >>>>> >>>>> I would like to be able to define the body of a SPIN function that >>>>> returns two variables, e.g. >>>>> >>>>> SELECT ?x ?y >>>>> WHERE { >>>>> ?example test:x ?x . >>>>> ?example text:y ?y . >>>>> } >>>>> >>>>> My question is: if such a function is possible, how are the results >>>>> bound when the function is called? In my experience with SPIN I have >>>>> written functions that return one variable, and thus the result is bound >>>>> to >>>>> a single variable when the function is called. For example, if I have a >>>>> SPIN function called "functionA" where the spin:body is: >>>>> >>>>> SELECT ?a >>>>> WHERE { >>>>> ?example test:a ?a . >>>>> } >>>>> >>>>> I would call this function and bind the result as >>>>> >>>>> BIND(:functionA(?aVariable) AS ?returnedA) . >>>>> >>>>> Is it possible to write a similar function that returns two (or more) >>>>> variables? >>>>> >>>>> Any help is appreciated! >>>>> >>>>> Alison >>>>> -- >>>>> -- You received this message because you are subscribed to the Google >>>>> Group "TopBraid Suite Users", the topics of which include Enterprise >>>>> Vocabulary Network (EVN), TopBraid Composer, TopBraid Live, >>>>> TopBraid Ensemble, SPARQLMotion, SPARQL Web Pages and SPIN. >>>>> To post to this group, send email to >>>>> [email protected] >>>>> To unsubscribe from this group, send email to >>>>> [email protected] >>>>> For more options, visit this group at >>>>> http://groups.google.com/group/topbraid-users?hl=en >>>>> --- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "TopBraid Suite Users" group. >>>>> To unsubscribe from this group and stop receiving emails from it, send >>>>> an email to [email protected]. >>>>> For more options, visit https://groups.google.com/groups/opt_out. >>>>> >>>>> >>>>> >>>> -- >>>> -- You received this message because you are subscribed to the Google >>>> Group "TopBraid Suite Users", the topics of which include Enterprise >>>> Vocabulary Network (EVN), TopBraid Composer, TopBraid Live, >>>> TopBraid Ensemble, SPARQLMotion, SPARQL Web Pages and SPIN. >>>> To post to this group, send email to >>>> [email protected] >>>> To unsubscribe from this group, send email to >>>> [email protected] >>>> For more options, visit this group at >>>> http://groups.google.com/group/topbraid-users?hl=en >>>> --- You received this message because you are subscribed to the Google >>>> Groups "TopBraid Suite Users" group. >>>> To unsubscribe from this group and stop receiving emails from it, send >>>> an email to [email protected]. >>>> For more options, visit https://groups.google.com/groups/opt_out. >>>> >>>> >>>> >>> -- >>> -- You received this message because you are subscribed to the Google >>> Group "TopBraid Suite Users", the topics of which include Enterprise >>> Vocabulary Network (EVN), TopBraid Composer, TopBraid Live, >>> TopBraid Ensemble, SPARQLMotion, SPARQL Web Pages and SPIN. >>> To post to this group, send email to >>> [email protected] >>> To unsubscribe from this group, send email to >>> [email protected] >>> For more options, visit this group at >>> http://groups.google.com/group/topbraid-users?hl=en >>> --- >>> You received this message because you are subscribed to the Google >>> Groups "TopBraid Suite Users" group. >>> To unsubscribe from this group and stop receiving emails from it, send >>> an email to [email protected]. >>> For more options, visit https://groups.google.com/groups/opt_out. >>> >>> >>> >>> > -- -- You received this message because you are subscribed to the Google Group "TopBraid Suite Users", the topics of which include Enterprise Vocabulary Network (EVN), TopBraid Composer, TopBraid Live, TopBraid Ensemble, SPARQLMotion, SPARQL Web Pages and SPIN. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/topbraid-users?hl=en --- You received this message because you are subscribed to the Google Groups "TopBraid Suite Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
