Hi Martynas,
if you suggest to rely on Jena rules to walk the superclasses for SPIN
then this is certainly an option but feels like an overkill to a
relatively simple problem. It would require to activate inferencing,
which has its own price tag and cannot be applied in all cases. Having
said this, an alternative SPIN implementation could certainly use that
machinery.
Holger
On 9/27/2015 0:51, Martynas Jusevicius wrote:
Hey Holger,
by inspecting SPINConstructors, I have noticed that constructors (and
probably constraints as well?) are "inherited" by walking up the
subclass chain and looking for them. Am I right?
I had a similar use case implemented as custom Jena rules. Properties
can be inferred by constructing OntModelSpec with GenericRuleReasoner
which parses the rules. They could look something like that:
[constructors: (?class rdf:type rdfs:Class), (?class
<http://spinrdf.org/spin#constructor> ?o), (?subClass rdfs:subClassOf
?class), noValue(?subClass <http://spinrdf.org/spin#constructor>) ->
(?subClass <http://spinrdf.org/spin#constructor> ?o) ]
[constraints: (?class rdf:type rdfs:Class), (?class
<http://spinrdf.org/spin#constraint> ?o), (?subClass rdfs:subClassOf
?class), noValue(?subClass <http://spinrdf.org/spin#constraint>) ->
(?subClass <http://spinrdf.org/spin#constraint> ?o) ]
I think that would be a cleaner approach and a better reuse of Jena's
machinery. Would that work for SPIN API?
Martynas
graphityhq.com
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