Thx Holger, That worked….
Where could I have find this info ? I tried: http://www.topquadrant.com/docs/TBC-Getting-Started-Guide40.pdf (version suggetsed 40 but actually 4.5) http://www.topquadrant.com/resources/knowledge-assets/docs/TBC_FeaturesOverview.pdf (version 3.5...) help info (it says only: “Note that OWL 2<http://127.0.0.1:50595/help/ntopic/org.topbraidcomposer.core/html/OWL_2.htm> provides an additional construct to conveniently define a class as the union of multiple disjoint classes.”) Thx michel Dr. ir. H.M. (Michel) Bohms Sr. Research Scientist Structural Reliability T +31 (0)88 866 31 07 M +31 (0)63 038 12 20 E [email protected]<mailto:[email protected]> Location<http://www.tno.nl/locaties/DTM> [cid:[email protected]]<http://www.tno.nl/> This message may contain information that is not intended for you. If you are not the addressee or if this message was sent to you by mistake, you are requested to inform the sender and delete the message. TNO accepts no liability for the content of this e-mail, for the manner in which you use it and for damage of any kind resulting from the risks inherent to the electronic transmission of messages. From: [email protected] [mailto:[email protected]] On Behalf Of Holger Knublauch Sent: dinsdag 29 september 2015 0:50 To: [email protected] Subject: Re: [topbraid-users] questions on disjoint classes On 9/28/2015 21:30, Bohms, H.M. (Michel) wrote: 1. How can I define AllDisjointClasses? In TBC - “owl:members” is not showing automatically when instantiating owl:AllDisjointClasses. Yes, this is because the rdfs:domain of owl:members is rdfs:Resource, and the OWL metamodel doesn't tell us that this property is supposed to work with owl:AllDisjointClasses etc only. To see that property, use the Add widget for property button. - And if you add it, filling in say (:Sub1 :Sub2 :Sub3) does not work The syntax expected by TBC is [item1, item2, ...] as shown in the screenshot: [cid:[email protected]] - Even coping the right code in the code tab does not work - So there must be another way to do it I guess….. 2. When I define disjoint class for class B at A, 2why do I not see it the other way round ? a. Does it need reasoning first? Yes to see the inverse values of a symmetric property, you'd need to run inferencing, e.g. the SPIN OWL RL rules. With SPIN OWL RL, note that you need to configure inferencing to also include the RDF/OWL system triples, and to activate Complete Mode. HTH Holger -- You received this message because you are subscribed to the Google Group "TopBraid Suite Users", the topics of which include Enterprise Vocabulary Network (EVN), Reference Data Manager (RDM), TopBraid Composer, TopBraid Live, TopBraid Insight, SPARQLMotion, SPARQL Web Pages and SPIN. To post to this group, send email to [email protected]<mailto:[email protected]> --- You received this message because you are subscribed to the Google Groups "TopBraid Suite Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]<mailto:[email protected]>. For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Group "TopBraid Suite Users", the topics of which include Enterprise Vocabulary Network (EVN), Reference Data Manager (RDM), TopBraid Composer, TopBraid Live, TopBraid Insight, SPARQLMotion, SPARQL Web Pages and SPIN. To post to this group, send email to [email protected] --- You received this message because you are subscribed to the Google Groups "TopBraid Suite Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
