On 19/02/2018 23:59, sanjeev devireddy wrote:
Hi,
We have the following two challenges while fetching/parsing the
list of preferred/alternative labels received from the the SPARQL
Endpoint service response.
1)To get the preferred/alternative label(s) without language tags. We
just want to check that is there a way to get the labels without
language tags?
You can convert a language-tagged string literal to a simple xsd:string
literal using the built-in str function, e.g.
SELECT *
WHERE {
?concept skos:prefLabel|skos:altLabel ?label .
BIND (str(?label) AS ?stringLabel) .
}
2)When there is a comma in the labels of preferred/alternative labels
(please check the below example).
Assume that there a single concept named Latin America, North
America. As shown below, we can see that there are two labels of the
languages English & French. Here we can observe that in each language
label there is a comma. In this case, using comma as a separator will
fail to get the English & French language labels of a single concept
Latin America, North America.
"prefLabel_0": { "type": "literal" , "value": "Latin America,
North America(en), Amérique latine, Amérique du Nord(fr)" }
So we just want to check what could be the best way in this kind of
scenario?
So you want the query to return all sub-strings as separated by commas?
The following example will produce an iteration over all substrings, and
trim them off extra spaces in case the string is irregular.
SELECT *
WHERE {
BIND ("Latin America, North America(en), Amérique latine, Amérique
du Nord(fr)" AS ?str)
?sub spif:split (?str ",") .
BIND (spif:trim(?sub) AS ?trimmed) .
}
To get rid of the language tags, you'd need to do further string
processing using functions like spif:indexOf and SUBSTR.
HTH
Holger
--
You received this message because you are subscribed to the Google Groups "TopBraid
Suite Users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/d/optout.
