Equivalent means that every single member of class A is also a member of class B and vice versa.
It also means the class A is a subclass of B and class B is a subclass of A. With this, every restriction defined for class A and for class B is applicable for all instances. If this is what you mean to say, then use equivalent class. I can’t say if this could or could not ever be true for two independently developed ontologies. It depends on the ontologies and intentions of their authors. SKOS has various ‘match’ predicates. However, I would not use SKOS predicates to connect classes. You could create your own and say that it is intended to connect classes. Semantics of SKOS predicates is not defined, anyhow, beyond the fact that they are intended for use with SKOS Concepts. > On Sep 3, 2019, at 10:03 AM, 'Bohms, H.M. (Michel)' via TopBraid Suite Users > <[email protected]> wrote: > > > Suppose I have two independent sources: one having class X and the other > having class Y where people think looking at the classes in isolation that > the two are the same. So they link them with equivalentclass. > > But they have different hierarchy with potential diff. restrictions “above”. > > Can it really be equivalent classes then? > > If here is just another taxonomy above they infer their own generic class > instances but what happens if restrictions are not satisfied. > > In general: is it possible to have equiv. class links really if classes are > from diff. sources? > (aren’t they always subtly different?) > Maybe only possible to use say skos:related or something weak like that? > > Thx for advice Michel > > > > > > > > Dr. ir. H.M. (Michel) Böhms > Senior Data Scientist > > T +31888663107 > M +31630381220 > E [email protected] > Location > > > <image001.gif> > This message may contain information that is not intended for you. If you are > not the addressee or if this message was sent to you by mistake, you are > requested to inform the sender and delete the message. TNO accepts no > liability for the content of this e-mail, for the manner in which you use it > and for damage of any kind resulting from the risks inherent to the > electronic transmission of messages. > > > > > -- > You received this message because you are subscribed to the Google Groups > "TopBraid Suite Users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion on the web visit > https://groups.google.com/d/msgid/topbraid-users/8d43cf24137942f3940ac5c925967795%40tno.nl. -- You received this message because you are subscribed to the Google Groups "TopBraid Suite Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/topbraid-users/C4749267-103F-4560-8A2B-092BC1D6DC93%40topquadrant.com.
